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A bullet of mass 20 g is horizontally fired with a velocity of 150 m/s from a pistol of mass 2 kg .what is the recoil velocity of the pistol
We have the following data:
ΔP (momentum before impact) = ?
mA (mass) = 20 g → 0.02 kg
vA (velocity) = 150 m/s
mB (mass) = 2 kg
vB (velocity) = ? (in m/s)
We apply the conservation law to the amount of motion:
*** Note¹: Law of conservation of momentum, since the total momentum of body A and B before impact is equal to the total momentum of body A and B after impact.
*** Note²: They will have velocities in opposite directions and it can be observed that if we multiply the mass of each one by their respective velocity, the result of this operation will be the same for both.
The recoil velocity of the pistol is 1.5 m/s
In the container with hot water in it.
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