An ideal fluid, of density 0.90 × 103 kg/m3, flows at 5.0 m/s through a level pipe with radius of 0.5 cm. the pressure in the fluid is 1.3 × 105 n/m2. this pipe connects to a second level pipe, with radius of 1.6 cm. find the speed of flow in the second pipe.
The speed of flow in the second pipe is 0.49 m/s
In our case, this problem shows a Fluid flow. We are to solve the speed flow of fluid to the second pipe.
For the formula, we will be using the Continuity equation for Fluid flow.
is the area of the first pipe
is the speed of fluid flowing in the first pipe
is the area of the second pipe
is the speed of fluid flowing in the second pipe
For the given information
this is the radius of the first pipe
Solving the problem
Here, we focus only to solve for the speed flow of fluid in the second pipe, so we will not be needing the other information stated in the problem.
Use the continuity equation, substitute the given information.
Deriving the equation, we have:
Take note that the area for the inlet of a pipe is a circle, therefore the area of a circle is,
Substitute the area of circle in the derived formula for continuity equation, we have:
Therefore, the speed flow on the second pipe is 0.49 m/s which means that the speed flow on the second pipe slows down.
To learn more about this topic, just click on the following links;Definition of Bernoulli's principle
The distance between the card and the wall is B. 0.750 m
focus of the convex lens = f = 0.120 m
diameter of hole = d = 0.005 m
diameter of image = d' = 0.020 m
distance between the card and the wall = s + s' = ?
distance between the card and the lens = s
distance between the wall and the lens = s'
→ Equation 1
← Equation 1
Convex Lens :
A car travels 35.0 mph north for 1.00 hour, then 40.0 mph east for 0.0500 hour, and finally 50.0 mph northeast for 2.00 hours. Calculate the average speed. v = mph
We have the following data:
* velocity (in mph)
(V1) = 35.0 mph
(V2) = 40.0 mph
(V3) = 50.0 mph
* weights for the time (in hours)
(T1) = 1.00 hour
(T2) = 0.0500 hour
(T3) = 2.00 hours
We apply the data to the weighted average formula to find the average speed, let us see:
The Average Speed is approximately 44.92 mph