The horizontal distance traveled by the bomb is 690.1 m
The given problem is an example of a free falling body. Here, the initial velocity of the bomb is the horizontal velocity of the plane because the plane is constantly moving with a speed before the bomb was dropped.
To analyze the problem, a free body diagram (FBD) was illustrated below.
Formula to be use
a. equation 1
b. equation 2
Solving the problem
1. Use equation 1 to solve for the time
Simplify and arrange the equation to standard form
Solve for the time using quadratic equation
t = 27.604 seconds
(Note: we only take the positive value of time and reject the negative)
2. Use equation 2 to solve for the horizontal distance traveled by the bomb
x = 690.1 m
Therefore, the horizontal distance traveled by the bomb is 690.1 m
To learn more about free falling bodies, just click on the following links:Recommendations on free falling bodies
Forces affecting the motion of a falling body
You don't need to multiply the only requirement is the number of significant figures.
heat is the hot feeling in a object while temperature is the measurement of hotness and coldness of a object
Given the formula for Potential Energy, PE = mgh,
*where PE = 22.5 J, g = 9.8 m/s^2 & h = 10 m
We will just substitute the given (& hidden) values to the formula in order to find out the mass of the fruit.
Since we are solving for mass, then we will use the formula: m = PE/gh
m = PE / gh
m = (22.5 J) / (9.8 m/s^2)(10 m)
m = 22.5 J / (980 m^2/s^2)
m = 22,050 kg